![Equazioni 1°, 2°, parametriche, di grado superiore: {\left|{2}{x}-{1 }\right|}={\left|{x}+{1}\right|}+{\left|{x}-{2}\right|} Equazioni 1°, 2°, parametriche, di grado superiore: {\left|{2}{x}-{1 }\right|}={\left|{x}+{1}\right|}+{\left|{x}-{2}\right|}](https://www.skuola.net/news_foto/2017/10/equ_e10.jpg)
Equazioni 1°, 2°, parametriche, di grado superiore: {\left|{2}{x}-{1 }\right|}={\left|{x}+{1}\right|}+{\left|{x}-{2}\right|}
![Prove that the equation x^3-2x+1=0 is satisfied by putting x either of the values sqrt{2}sin 45^o, 2sin 18^o, and 2sin 234^o. Prove that the equation x^3-2x+1=0 is satisfied by putting x either of the values sqrt{2}sin 45^o, 2sin 18^o, and 2sin 234^o.](https://haygot.s3.amazonaws.com/questions/1715544_1730575_ans_7ae022f5833242759b561e2e4c67b155.jpg)
Prove that the equation x^3-2x+1=0 is satisfied by putting x either of the values sqrt{2}sin 45^o, 2sin 18^o, and 2sin 234^o.
![Disequazioni: {\left|\frac{{{2}{x}+{5}}}{{{4}{x}-{2}}}-\frac{{{x}-{1}}}{{{1 }-{2}{x}}}\right|}\lt\frac{2}{{3}} Disequazioni: {\left|\frac{{{2}{x}+{5}}}{{{4}{x}-{2}}}-\frac{{{x}-{1}}}{{{1 }-{2}{x}}}\right|}\lt\frac{2}{{3}}](https://www.skuola.net/news_foto/2017/10/dise_e2-615x724.jpg)
Disequazioni: {\left|\frac{{{2}{x}+{5}}}{{{4}{x}-{2}}}-\frac{{{x}-{1}}}{{{1 }-{2}{x}}}\right|}\lt\frac{2}{{3}}
What is the solution of '2x² - 2x +1/2 = 0' using factorization method? - Mathematics is Life - Quora
![Disequazione: \frac{{{x}+{\left|{x}-{1}\right|}+{3}-{2}{\left({x }-{3}\right)}}}{{{\left|{x}\right|}-{\left|{x}^{2}-{1}\right|}}}\ge{0} Disequazione: \frac{{{x}+{\left|{x}-{1}\right|}+{3}-{2}{\left({x }-{3}\right)}}}{{{\left|{x}\right|}-{\left|{x}^{2}-{1}\right|}}}\ge{0}](https://www.skuola.net/news_foto/2017/10/dise_e6.jpg)
Disequazione: \frac{{{x}+{\left|{x}-{1}\right|}+{3}-{2}{\left({x }-{3}\right)}}}{{{\left|{x}\right|}-{\left|{x}^{2}-{1}\right|}}}\ge{0}
![If left| x right| <1 prove that dfrac { 1-2x }{ 1-x+{ x }^{ 2 } } +dfrac { 2x-{ 4x }^{ 3 } }{ 1-{ x }^{ 2 }+{ x }^{ 4 } } +dfrac { 4{ x }^{ 3 }-8{ x }^{ 7 } }{ 1-{ x }^{ 4 }+{ x }^{ 8 } } +.....infty =dfrac { 1+2x }{ 1+x+{ x }^{ 2 } } If left| x right| <1 prove that dfrac { 1-2x }{ 1-x+{ x }^{ 2 } } +dfrac { 2x-{ 4x }^{ 3 } }{ 1-{ x }^{ 2 }+{ x }^{ 4 } } +dfrac { 4{ x }^{ 3 }-8{ x }^{ 7 } }{ 1-{ x }^{ 4 }+{ x }^{ 8 } } +.....infty =dfrac { 1+2x }{ 1+x+{ x }^{ 2 } }](https://haygot.s3.amazonaws.com/questions/1973555_1550467_ans_83e456faf686416c9504ccf4fec22193.jpeg)
If left| x right| <1 prove that dfrac { 1-2x }{ 1-x+{ x }^{ 2 } } +dfrac { 2x-{ 4x }^{ 3 } }{ 1-{ x }^{ 2 }+{ x }^{ 4 } } +dfrac { 4{ x }^{ 3 }-8{ x }^{ 7 } }{ 1-{ x }^{ 4 }+{ x }^{ 8 } } +.....infty =dfrac { 1+2x }{ 1+x+{ x }^{ 2 } }
![Nippli riduzione 1/2 X 1/4 vite doppia ridotta zincata 245102144 | Idrastore.it - Forniture idrauliche ed arredobagno Nippli riduzione 1/2 X 1/4 vite doppia ridotta zincata 245102144 | Idrastore.it - Forniture idrauliche ed arredobagno](https://www.idrastore.it/176493-large_default/nippli-riduzione-1-2-x-1-4-vite-doppia-ridotta-zincata.jpg)