![Esercizi sui limiti: \lim_{{{x}\to{1}}}\frac{{\left({x}^{2}-{2}{x}+{1 }\right)}^{2}}{{{x}^{2}-{6}{x}+{5}}}\cdot\frac{1}{{{x}^{2}-{5}{x}+{4}}} Esercizi sui limiti: \lim_{{{x}\to{1}}}\frac{{\left({x}^{2}-{2}{x}+{1 }\right)}^{2}}{{{x}^{2}-{6}{x}+{5}}}\cdot\frac{1}{{{x}^{2}-{5}{x}+{4}}}](https://cdn.skuola.net/w1200h1039/news_foto/images/stories/esercizi/limx-1x2-2x12x2-6x.jpg)
Esercizi sui limiti: \lim_{{{x}\to{1}}}\frac{{\left({x}^{2}-{2}{x}+{1 }\right)}^{2}}{{{x}^{2}-{6}{x}+{5}}}\cdot\frac{1}{{{x}^{2}-{5}{x}+{4}}}
Evaluate the integral: ∫(2x + 1)/√(x^2 + 2x - 1) dx - Sarthaks eConnect | Largest Online Education Community
![Disequazioni: {\left|\frac{{{2}{x}+{5}}}{{{4}{x}-{2}}}-\frac{{{x}-{1}}}{{{1 }-{2}{x}}}\right|}\lt\frac{2}{{3}} Disequazioni: {\left|\frac{{{2}{x}+{5}}}{{{4}{x}-{2}}}-\frac{{{x}-{1}}}{{{1 }-{2}{x}}}\right|}\lt\frac{2}{{3}}](https://www.skuola.net/news_foto/2017/10/dise_e2-615x724.jpg)